Answer:
A. The relative minimum point is (3/2, f(3/2)).
To find the relative extrema of the function f(x)=7−3x+x^2, we need to find the critical points by setting the derivative equal to zero.
Taking the derivative of f(x), we get:
f’(x) = -3 + 2x
Setting f’(x) equal to zero, we have:
-3 + 2x = 0
Solving for x, we find:
2x = 3
x = 3/2
The critical point occurs at x = 3/2.
To determine the type of extrema at this critical point, we can use the second derivative test. Taking the derivative of f’(x), we get:
f’’(x) = 2
Since the second derivative is positive, f’’(x) > 0, the function has a relative minimum at x = 3/2.
Therefore, the correct choice is:
A. The relative minimum point is (3/2, f(3/2)).