Question

Find three consecutive odd integers such that the difference of twice the largest and four times the smallest is 54 .

Answer 1

Let's denote the three consecutive odd integers as "x," "x + 2," and "x + 4."

According to the problem, the difference of twice the largest and four times the smallest is 54:

2 * (x + 4) - 4 * x = 54

Simplify the equation:

2x + 8 - 4x = 54

Combine like terms:

-2x + 8 = 54

Subtract 8 from both sides:

-2x = 46

Divide by -2:

x = -23

So, the three consecutive odd integers are -23, -21, and -19.