Answer:
The limiting reagent in this reaction is iron (II) chloride, since 53 grams of iron (II) chloride is present, but only 14 grams of sodium phosphate. This means that the reaction will be limited by the amount of iron (II) chloride, and the amount of sodium phosphate will not be consumed completely.
The amount of sodium chloride that can be formed is determined by the amount of iron (II) chloride present. Since 53 grams of iron (II) chloride is present, the maximum amount of sodium chloride that can be formed is 53 grams.