Question

2. Together, two students exert a force of 825 N in pushing a car a distance of 35 m. a. How much work do the students do on the car? b. If their force is doubled, how much work must they do on the car to push it the same distance?​

Answer 1

W1 = F1 × distance

F1 = 825 N

F2 = 2 × F1

so, W2 = F2 × distance = (2 × F1) × distance

so, W2 = 2 (F1 × distance) = 2 × W1

Step-by-step explanation:

(a) W1 = 825 × 35 = 28,875 Joule

(b) W2 = 2 × 28,875 = 57,750 Joule