Answer:
To find the percentage of workers who earn more than $18.50, you can use the standard normal distribution (z) scores and the z-table.
First, calculate the z-score for the value $18.50 using the formula:
\[ z = \frac{x - \mu}{\sigma} \]
where \( x \) is the value, \( \mu \) is the mean, and \( \sigma \) is the standard deviation.
Given:
- Mean \( \mu = 13.50 \)
- Standard deviation \( \sigma = 2.50 \)
- Value \( x = 18.50 \)
Calculating the z-score:
\[ z = \frac{18.50 - 13.50}{2.50} = 2 \]
Next, use the z-table to find the percentage of values greater than the z-score of 2. The z-score of 2 corresponds to an area of approximately 0.9772 in the z-table.
To find the percentage of workers earning more than $18.50:
\[ \text{Percentage} = (1 - 0.9772) \times 100 \approx 2.28\% \]
Rounded to the nearest hundredth of a percent, the answer is approximately 2.28%.