To achieve a 95% confidence interval with a margin of error of 25 points, you need to sample approximately 169 students.
For estimating the sample size needed to achieve a certain margin of error in a confidence interval, you can use the formula:
\[ n = \left( \frac{Z \cdot \sigma}{E} \right)^2 \]
Where:
- \( n \) is the sample size
- \( Z \) is the Z-score corresponding to the desired confidence level (for 95% confidence, \( Z = 1.96 \))
- \( \sigma \) is the population standard deviation (300 in this case)
- \( E \) is the desired margin of error (25)
Plugging in the values:
\[ n = \left( \frac{1.96 \cdot 300}{25} \right)^2 \approx 168.48 \]
Since you can't have a fraction of a student, you would round up to the nearest whole number. Therefore, you should sample around 169 students.
To ensure a 95% confidence interval with a margin of error of 25 points when estimating the average SAT score of first-year students, you need to sample approximately 169 students. This sample size accounts for the population mean of 1,500 and the population standard deviation of 300.