Question

Write a system of two quadratic equations that has solutions of (-3,-3)and (3,-3)

Answer 1

Explanation:

the solution (-3, -3):

-3 = a(-3)^2 + b(-3) + c

-3 = 9a - 3b + c (Equation)

the solution (3, -3):

-3 = a(3)^2 + b(3) + c

-3 = 9a + 3b + c (Equation 2)

Combining both equations, we have the system:

9a - 3b + c = -3

9a + 3b + c = -3

Simplifying this system, we get:

9a - 3b + c = -3

9a + 3b + c = -3