Question

General Form fined by the equation x=-(1)/(40)y^(2)+(3)/(10)y+(71)/(10).

Answer 1

The general form of the equation is given by:

x = -(1/40)y^2 + (3/10)y + 71/10

In general form, the equation is represented as:

ax^2 + bx + c = 0

So, comparing the given equation with the general form, we can see that:

a = -1/40

b = 3/10

c = 71/10