Answer:
Explanation:
To find the equation of a line that is perpendicular to the given line and passes through the point (9, 2), we need to follow these steps:
 Find the slope of the given line.
 Determine the negative reciprocal of the slope (perpendicular slope).
 Use the point-slope form of a linear equation to write the equation.
Given line: 3x - y = 9
 Find the slope of the given line:
 The equation is in the form y = mx + b, where "m" is the slope. Rearrange the equation to solve for y:
 y = 3x - 9
So, the slope of the given line is 3.
 Determine the negative reciprocal of the slope:
 The negative reciprocal of 3 is -1/3.
 Use the point-slope form of a linear equation (y - y₁ = m(x - x₁)):
 Point: (9, 2)
 Slope: -1/3
Now plug in the values to get the equation:
y - 2 = -1/3(x - 9)
Simplify the equation:
y - 2 = -1/3x + 3
Add 2 to both sides:
y = -1/3x + 5
So, the equation of the line that is perpendicular to 3x - y = 9 and passes through the point (9, 2) is y = -1/3x + 5.