Final answer:
The tension in the wire of a simple pendulum when the bob is directly below its point of support is equal to the weight of the mass. For a mass of 8.500 kg and gravity of 9.807 m/s², the tension is approximately 83.36 Newtons.
Step-by-step explanation:
The question asks for the magnitude of the tension in the wire of a simple pendulum when the bob is directly below its point of support. The tension in the string is solely due to the weight of the mass at this position. Assuming the pendulum is at the equilibrium position and not moving, the tension is equal to the gravitational force acting on the mass. The gravitational force, also known as the weight of the bob, is calculated by multiplying the mass m by the acceleration due to gravity g.
Using the given values, mass m = 8.500 kg and gravitational acceleration g = 9.807 m/s2, the magnitude of tension (T) is:
T = m * g
T = 8.500 kg * 9.807 m/s2
T = 83.3595 N
Therefore, the tension in the wire when the pendulum bob is directly below its point of support is approximately 83.36 Newtons.