Question

Def complementary_color(color): if ___ == "blue": complement = "orange" elif ___ == "yellow": complement = "purple" elif ___ == "red": complement = "green" ___: complement = "unknown" return ___

Answer 1

The subject of this question is Computer Science, and the grade is High School. The code defines a function called complementary_color that determines the complement of the given color using if-elif-else statements. The correct code for the function is provided.

Step-by-step explanation:

The subject of this question is Computer Science and the grade level is High School.

The given code defines a function called complementary_color that takes a color as a parameter. The function uses the if-elif-else statement to determine the complement of the given color. In this code, if the color is blue, the complement is orange. If the color is yellow, the complement is purple. If the color is red, the complement is green. If none of the previous conditions are met, then the complement is unknown.

The correct code for this function is:

def complementary_color(color):
if color == "blue":
complement = "orange"
elif color == "yellow":
complement = "purple"
elif color == "red":
complement = "green"
else:
complement = "unknown"
return complement