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4 votes
Solve the system of equations using elimination 5x-y=28 and 3x+2y=9

1 Answer

4 votes

Answer:

5x-y=28

3x+2y =9

by multiplying the 1st equation by 2

2(5x-y)=28)

---->10x-2y=56

10x-2y=56

3x+2y=9

--->13x=65

x=65/13=5

x=5

we calculate y:

5x-y=28

5*5 -y=28

y=28-25=3

y=3

answers{5;3}

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