Question

Using the equation of the straight line 4y-10x+20=0 , find the point where the line cut the y axis.​

Answer 1

y - intercept= -20

Explanation:

the equation of the straight line is,

ax + by = c

where c is the y-intercept i.e. the point where the line cuts the y-axis

according to the given equation,

-10x + 4y = -20

thus, y - intercept = -20