Question

The equation of the line that passes through the points $(-2,0)$ and $(0,2)$ can be expressed in the form y=mx+b. What is the value of m+b?

Answer 1

y = x + 2

m = 1

b = 2

1 + 2 = m + b = 3

Explanation:

(-2, 0) and (0, 2)

y = mx + b is the slope-intercept form where m is the slope and b is the y-intercept

first let's solve for the slope of the line

m = slope

m =
`(y_2-y_1)/(x_2-x_1)`

m =
`(2-0)/(0-(-2))`

m = 2/2 or 1

Then using the slope we can find the y-intercept by plugging in the slope and using one of the given points

y = mx + b

(You can use any point)

2 = 1(0) + b

2 = 0 + b

b = 2 - 0

b = 2

The y-intercept of the line is 2