Question

Use the Laws of Logarithms to evaluate the expression. log_(6)(216)+log_(6)(6)

Answer 1

`\log_(6)216+\log_(6)6\\=\log_(6)6^3+1\ \ \ \[[\mathrm{log_(a)a=1,\ a \\e 1, a\\e0}]\\=3+1\ \ \ \ [\mathrm{log_(a)a^n=n,\ a \\e 1, a\\e0}]\\=4`