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Write the equation of the line given points (1 , 3) and (-2 , 5):

Parallel slope:

Perpendicular slope:

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User Evgen
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1 Answer

5 votes

Answer:

Parallel slope: -2/3.

Perpendicular slope: 3/2.

Explanation:

To find the equation of the line passing through the given points (1, 3) and (-2, 5), we need to calculate the slope of the line first.

Slope (m) = (change in y) / (change in x)

Slope = (5 - 3) / (-2 - 1) = 2 / -3

Now that we have the slope, use the point-slope form of a linear equation to find the equation of the line:

y - y1 = m(x - x1)

Using the point (1, 3):

y - 3 = (2 / -3)(x - 1)

Simplify this equation:

y - 3 = (-2/3)x + 2/3

To put the equation in slope-intercept form (y = mx + b), we can add 3 to both sides:

y = (-2/3)x + 2/3 + 3

y = (-2/3)x + 11/3

The equation of the line passing through the points (1, 3) and (-2, 5) is

y = (-2/3)x + 11/3.

Calculate the slopes for lines that are parallel and perpendicular to this line.

Parallel slope: The slope of a line parallel to this one will be the same, which is -2/3.

Perpendicular slope: The slope of a line perpendicular to this one will be the negative reciprocal of the slope. Therefore, the perpendicular slope is 3/2.

answered
User Abdul Muneer
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8.5k points

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