Question

A square is inscribed in a right isosceles triangle, such that two of its vertices lie on the hypotenuse and two other on the legs. Find the length of the side of the square, if the length of the hypotenuse is 3 in.

Pls provide full explanation.. I need help fastt

Answer 1

Hi,

All you have to do is to divide the hypotenuse by 3.

The length of the square is thus 1 in.

Explanation:

Let's assume x the length of the square:

The triangles ADG and BEH are also right isosceles triangles ( there is an angle of 45°)

AD=DE=EB=x = 3/3 in = 1 in