Question

A rock is thrown downward from a certain height. The height s(t) in meters of the rock as a function of time t in seconds is given by s(t) = -4.9t^(2) -34.3t + 20 How high above the ground is the bridge?

Answer 1

Step-by-step explanation:

At time t= 0 the rock is at the bridge ( before it is thrown downward)

-4.9(0)^2 - 34.3(0) + 20 = 20 meters high