Question

In a right-angled triangle,base=12cm and hypotenuse =15cm.find the perpendicular

Answer 1

`\mathrm{Solution:}\\\mathrm{Base(b)=12cm}\\\mathrm{Hypotenuse(h)=15cm}\\\mathrm{Perpendicular(p)=?}\\\mathrm{Using\ Pythagoras\ theorem,}\\\mathrm{h^2=p^2+b^2}\\\mathrm{or,\ 15^2=p^2+12^2}\\\mathrm{or,\ p^2=81}\\\mathrm{or,\ p=\pm9}\\\mathrm{p=-9\ cannot\ be\ possible\ as\ length\ cannot\ be\ negative.}\\\mathrm{\therefore\ perpendicular(p)=9cm}`

Answer 2

9

Explanation:

With hypotenuse = 15 and with the equation a^2 + b^2 = C^2.

15 = c

12 = a or b

9 = a or b

Answer: 9