Question

2. Express 81 as the sum of first nine consecutive numbers.​

Answer 1

If you meant the first odd nine consecutive numbers this is the answer:
`1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 = 81`

Explanation:

I will interpret your answer by thinking of the first 9 ODD consecutive numbers since it is not possible with normal consecutive numbers.

Knowing that the sum of the first n odd natural numbers can be represented by
`n^2`, let's find the value of n when
`n^2` is equal to 81.

Upon taking the square root of 81, we get:

`n=9`

Therefore, we can deduce that the sum of the first nine consecutive odd numbers amounts to 81.

The sequence of the first nine consecutive odd numbers is 1, 3, 5, 7, 9, 11, 13, 15, and 17.

Hence, the required sum equals
`1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17`.

Hope this helps!!!

Answer 2

Explanation:

Divide 81 by 9 = 9 this is the middle number

5 + 6+ 7+ 8+ 9+ 10+ 11+ 12+ 13 = 81