Question

Find (ƒ – g)(x) where ƒ(x) = 2x2 + 5x – 8, g(x) = –x2 + 6x.

A. (ƒ – g)(x) = 3x2 – x – 8
B. (ƒ – g)(x) = x2 + 11x – 8
C. (ƒ – g)(x) = –3x2 + x + 8
D. (ƒ – g)(x) = –3x2 – x + 8

Answer 1

A

Explanation:

ƒ(x) = 2x2 + 5x – 8

g(x) = –x2 + 6x

(ƒ – g)(x)=2x2+5x-8-(-x2+6x)

=2x2+5x-8+x2-6x

=3x2-x-8