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Find the area of the polygon. Round to the nearest tenth.
30 cm- length
15 cm- height

Find the area of the polygon. Round to the nearest tenth. 30 cm- length 15 cm- height-example-1

2 Answers

5 votes

Answer:

626.7cm²

Explanation:

The area of the middle rectangular shape is simply 30(15) = 450cm²

As for the 2 semicircles, since they are congruent, we can just find the area of a full circle with the same radius.

As the diameter of each semicircle is 15cm, then the radius will be 15/2cm and hence the total area of both semicircles is π(15/2)² = (225/4)π. The area of the polygon is therefore 450 + (225/4)π cm²

answered
User Josianne
by
7.6k points
0 votes

Answer:

626.7 cm²

Explanation:

Given:

Middle one is rectangle.

Area of rectangle is given by: length* breadth

Area of rectangle = 30*15=450 cm^2

Again

if we join two half circle it will make a circle.

Area of two semi circle =
\sf \pi \:radius^2

Here

Radius = 15/2 =7.5 cm

Now

aAre of two semi circle =
\sf \pi 7.5^2=176.7 cm^2

Now,

Total area = Area of rectangle + Area of two semi circle

Total Area
\sf = 450 cm^2+ 176.7 cm^2

Total area =
\sf 626.7 cm^2

Therefore, the area of the polygon is
\sf 626.7 cm^2

answered
User RKumsher
by
7.7k points

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