Question

What are the zeros of the function f(x)=x^2-x-12/x^2+x-12

Answer 1

the zeros of the function f(x) are x = 4 and x = -3.

Explanation:

To find the zeros of the function f(x) = (x^2 - x - 12) / (x^2 + x - 12), we need to set f(x) equal to zero and solve for x:

f(x) = 0

(x^2 - x - 12) / (x^2 + x - 12) = 0

Now, since a fraction is equal to zero when its numerator is equal to zero, we can set the numerator equal to zero:

x^2 - x - 12 = 0

Now, let's factor the quadratic equation:

(x - 4)(x + 3) = 0

Now, we can set each factor equal to zero and solve for x:

1. x - 4 = 0

x = 4

2. x + 3 = 0

x = -3

So, the zeros of the function f(x) are x = 4 and x = -3.