Question

P(y)=(y+2)(y-1)
Find the value of p(y) at y= -1

Answer 1

Answer: -2

Explanation:

p(y) = (y + 2)(y -1)

p( - 1) = ( - 1 + 2 ) ( - 1 - 1 )

p( - 1) = 1 × ( - 2 )

p( - 1 ) = - 2

value of p(y) at y = -1 is -2

Answer 2

p(-1)=-2

Explanation:

p(y)=(y+2)(y-1)

p(-1)=(-1+2)(-1-1)

p(-1)=(1)(-2)

p(-1)=-2