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.Given f(x) = 3x + 1 when x ≤ 0; x² when 0 < x < 4; and x-5 when x ≥ 4, evaluate f(3). f(3) = 10 f(3) = 9 does not exist f(3) = -2

.Given f(x) = 3x + 1 when x ≤ 0; x² when 0 < x < 4; and x-5 when x ≥ 4, evaluate f(3). f(3) = 10 f(3) = 9 does not exist f(3) = -2
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.Given f(x) = 3x + 1 when x ≤ 0; x² when 0 < x < 4; and x-5 when x ≥ 4, evaluate f(3).

f(3) = 10

f(3) = 9

does not exist

f(3) = -2

asked
User Alex Van Rijs
by
8.2k points

1 Answer

0 votes

Answer:

f(3) = 9

Explanation:

f(3) should be in 0<x<4

so f(3) = 3^2

f(3) = 9

answered
User Ahmed Farahat
by
8.6k points
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