Question

We are interested in the dimensions of a certain rectangle. This rectangle has length twice the side of the square and width three units less than the side of this square. If the two areas are equal, what are the rectangle's dimensions (WxH)?

Answer 1

the length of square is 6 and length of rectangle is 12 and breadth of rectangle is 3

Explanation:

Let length of square be x

Given,

length of square = x

length of rectangle = 2x

breadth of rectangle = x-3

Area of square = Area of rectangle

Now

Area of square = Area of rectangle

or, length of square^2 = length * breadth of rectangle

or, x^2 = 2x(x-3)

or, x^2 / x = 2(x-3)

or, x = 2x-6

or, 2x-x-6=0

or, x-6=0

or, x=6

Therefore the value of x is 6

length of square is 6

length of rectangle is 2x = 12

breadth of rectangle is x-3 = 6-3 = 3