I NEED HELP AGAINNNNN (1)/(x+1) +(2)/(x+3)

Question

I NEED HELP AGAINNNNN

`(1)/(x+1) +(2)/(x+3)`

Answer 1

`(3x+5)/((x+1)(x+3))`

Explanation:

`(1)/(x+1)` +
`(2)/(x+3)`

before adding the fractions we require them to have a common denominator

To obtain this

multiply the numerator/ denominator of the first fraction by the denominator of the second fraction, that is (x + 3)

multiply the numerator/denominator of the second fraction by the denominator of the first fraction, that is (x + 1)

the common denominator will then be (x + 1)(x + 3)

=
`(x+3)/((x+1)(x+3))` +
`(2(x+1))/((x+1)(x+3))` ← simplify numerators

=
`(x+3+2x+2)/((x+1)(x+3))`

=
`(3x+5)/((x+1)(x+3))`