Answer:
two complex conjugate numbers
Explanation:
given a quadratic equation in standard form
ax² + bx + c = 0 ( a ≠ 0 )
then the discriminant
Δ = b² - 4ac , informs us about the nature of the solutions
• if b² - 4ac > 0 , then two real, irrational solutions
• if b² - 4ac > 0 and a perfect square, then two real, rational solutions
• if b² - 4ac = 0 , then one real, rational solution (double)
• if b² - 4ac < 0 , then two complex conjugate solutions
given
4x² - 7x + 4 = 0 ← in standard form
with a = 4, b = - 7 , c = 4 , then
b² - 4ac
= (- 7)² - (4 × 4 × 4)
= 49 - 64
= - 15
since b² - 4ac < 0 , then two complex conjugate solutions