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Which graph shows the solution to the system of linear equations? y = 2x − 2 4x − 2y = 4 Coordinate plane with one line that passes through the points 0 comma negative 2 and 1 comma 0. Coordinate plane with one line that passes through the points 0 comma negative 1 and 1 comma 1 and another line that passes through the points 0 comma negative 2 and 1 comma 0. Coordinate plane with one line that passes through the points 0 comma 1 and 1 comma 2. Coordinate plane with one line that passes through the points 0 comma negative 2 and 1 comma 0 and another line that passes through the points 0 comma 1 and 1 comma 2.

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Which graph shows the solution to the system of linear equations? y = 2x − 2 4x − 2y = 4 Coordinate plane with one line that passes through the points 0 comma negative 2 and 1 comma 0. Coordinate plane with one line that passes through the points 0 comma negative 1 and 1 comma 1 and another line that passes through the points 0 comma negative 2 and 1 comma 0. Coordinate plane with one line that passes through the points 0 comma 1 and 1 comma 2. Coordinate plane with one line that passes through the points 0 comma negative 2 and 1 comma 0 and another line that passes through the points 0 comma 1 and 1 comma 2.
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User Sulfureous
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Answer:

Coordinate plane with one line that passes through the points O comma negative 2 and 1 comma 0 and another line that passes through the points 0 comma 1 and 1 comma 2

Which graph shows the solution to the system of linear equations?

Step 1: The given system of equations is y = 2x-2 and 4x - 2y = 4.

Step 2: To graph this system of linear equations, we need to set up two equations in the form y = mx + b.

Step 3: The first equation can be written as y = 2x-2. This can be rearranged to be in the form y = mx + b, which is y = 2x + (-2).

So the slope of the line is 2 and the y-intercept is -2.

Step 4: The second equation can be written as 4x - 2y = 4.

This can be rearranged to be in the form y = mx + b, which is y = (4/2)x + (-2).

So the slope of the line is 4/2 and the y-intercept is -2.

Step 5: To graph this system of linear equations, we need to draw two lines on the coordinate plane.

The first line is the line with a slope of 2 and a y-intercept of -2, which passes through the points 0, -2 and 1, 0.

The second line is the line with a slope of 4.

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User Kmort
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