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If the area of a rectangle is A(x)=6x^2+21x and the width is 3x, what is the length?

If the area of a rectangle is A(x)=6x^2+21x and the width is 3x, what is the length?
asked 187k views
4 votes
If the area of a rectangle is A(x)=6x^2+21x and the width is 3x, what is the length?

asked
User Millicent
by
9.5k points

1 Answer

3 votes

Answer:

2x + 7

Explanation:

6x^2+21x ÷ 3x = 2x + 7

answered
User Charlie V
by
8.2k points
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