Question

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OBINPHYS8
5.P.005.
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A machinist wishes to insert a steel rod with a diameter of 8 mm into a hole with a diameter of 7.996 mm. By how much would the machinist have to lower the temperature (in "C) of the rod to make
it fit the hole?
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Answer 1

L = L0 (1 + α Δt) for coefficient of linear expansion

Δt = (L - L0) / (L0 α) solving for temperature change

for steel α = 1.2E-5 / deg C

Δt = -.004 / (8 * 1.2E-5 / deg C) = -40 deg C