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7 × 3 + [ 6 + 2 × (23 ÷ 4 + 3 × 2) – 7 × √4 ] + 9 ÷ 3
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3 votes

Answer:

40

Explanation:

We can simplify the expression using the Order of Operations (PEMDAS):

P arentheses

E xponents

M ultiplication

D ivision

A ddition

S ubtraction

But remember that {M and D} and {A and S} are interchangeable, so whichever one in the grouping comes first, you work out first.

7 × 3 + [ 6 + 2 × (24 ÷ 4 + 3 × 2) − 7 × √4 ] + 9 ÷ 3

↓ working inside the brackets (which act as parentheses)

[ 6 + 2 × (24 ÷ 4 + 3 × 2) − 7 × √4 ]

↓ working inside the parentheses

(24 ÷ 4 + 3 × 2)

↓ completing the division and multiplication ... 24 ÷ 4 = 6 ... 3 × 2 = 6

(6 + 6)

↓ completing the addition ... 6 + 6 = 12

(12)

↓ putting it back into the bracketed expression

[ 6 + 2 × (12) − 7 × √4 ]

↓ completing the multiplication ... 2 × 12 = 24 ... 7 × √4 = 7 × 2 = 14

[ 6 + 24 − 14 ]

↓ completing the addition ... 6 + 24 = 30

[ 30 − 14 ]

↓ completing the subtraction ... 30 − 14 = 16

[16]

↓ putting it back into the original expression

7 × 3 + [16] + 9 ÷ 3

↓ completing the multiplication and division ... 7 × 1 = 24 ... 9 ÷ 3 = 3

21 + [16] + 3

↓ completing the leftmost addition ... 21 + 16 = 37

37 + 3

↓ completing the addition ... 37 + 3 = 40

40

answered
User Hans Karlsen
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