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What is the correct Ka expression for the reaction below? H₂PO4 (aq) + H₂O(1) HPO42 (aq) + H₂O*(aq)

What is the correct Ka expression for the reaction below? H₂PO4 (aq) + H₂O(1) HPO42 (aq) + H₂O*(aq)
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What is the correct Ka expression for the reaction below?

H₂PO4 (aq) + H₂O(1) HPO42 (aq) + H₂O*(aq)

asked
User Aditya Mehta
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1 Answer

3 votes
The correct Ka expression for the reaction is:

Ka = [HPO42-][H₂O]/[H₂PO4-]
answered
User Maluen
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