4i^2 - 15i + 9 = 0 confused on how quadratic equations work

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asked Nov 4, 2024 85.0k views

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Akash Agarwal · Answer 1 · 2024-11-09T12:56:16+0000

First, we bring the equation to the form ax²+bx+c=0, where a, b, and c are coefficients. Then, we plug these coefficients in the formula: (-b±√(b²-4ac))/(2a) .

4i^2 - 15i + 9 = 0 confused on how quadratic equations work

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4i^2 - 15i + 9 = 0 confused on how quadratic equations work