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From a group of 28 students, how many ways can all 28 of them stand in a line

1 Answer

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Answer:

3.0488834461·10²⁹

Explanation:

There are 28 ways to put one student 1st in line

There are 27 ways to put the second student 2nd in line

There are 26 ways to put the third student 3rd in line

....

This can be represented with 28!, which means we multiply all positive integers starting with 28 all the way down to 1:

28! = 28*27*26*25*...*1 = 3.0488834461·10²⁹

That's a lot of possibilities!

answered
User Aerlfredith
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