Based on the above, the value that will be contained in x12 is 0x00ff0000.
The code given is one that initializes `x10` with `0x84ff`, shifts it left by 16 bits, then right by 16 bits (signed) into `x13`, and right by 8 bits into `x14`. The bitwise AND operation between `x13` and `x14` results in `x12`.
Therefore, The final value in `x12` is `0x00ff0000`. This is obtained by preserving the lower 8 bits and setting the higher bits to zero.
So, to calculate the final value contained in x12:
Start, x10 is 0x84ff.
After the slli operation, x12 be 0xff000000.
After the srai operation, x13 be 0xffffffff.
After the srli operation, x14 be 0x00ff0000.
Lastly, after the and operation, x12 be 0x00ff0000
Hence, the value contained in x12 is 0x00ff0000.
See text below
After the following code is run, what is contained in x12? answer with 8 digits of hexadecimal.
li x10, 0x84ff
slli x12, x10, 0x10
srai x13, x12, 0x10
srli x14, x12, 0x08
and x12, x13, x14