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Without using a calculator, fill in the blanks with two consecutive integers to complete the following inequality. ____< (Square root of) 32 <______



asked
User Elon
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2 Answers

4 votes

Answer:

5<square root of 32<6

Step-by-step explanation

:)

answered
User Dgarbacz
by
8.3k points
0 votes

Answer:


\boxed{5} < √(32) < \boxed{6}

Explanation:

To find the two consecutive integers that √(32) is between, we need to find the perfect squares that are above and below the square of √(32).

An integer is a whole number that can be either positive, negative, or zero, without any fractional or decimal parts.

A perfect square is a number that can be obtained by multiplying an integer by itself.

The first few perfect squares are:

  • 1² = 1
  • 2² = 4
  • 3² = 9
  • 4² = 16
  • 5² = 25
  • 6² = 36

The square of √(32) is 32.

The number 32 is between the perfect squares 25 and 36:

  • 25 < 32 < 36

Taking the square roots of each number in the inequality gives:

  • 5 < √(32) < 6

Therefore, the two consecutive integers that complete the given inequality are 5 and 6.

answered
User Ederbf
by
8.1k points

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