Question

Determine the approximate volume (in mL) of a 0.120 M solution that contains 10.0 g of copper(II) sulfate, CuSO4.

Answer 1

Related Concepts

• Moles
• Concentration
• Stoichiometry

Solution

We're given:

• C = 0.120 M
• m = 10.0 g

First, solve for the moles of CuSO₄:

`n=(m)/(M)\\\\n=(10.0g)/(160 g/mol)\\\\n=0.0625 mol`

Then, we can solve for volume:

`C=(n)/(V)\\\\V=(n)/(C)\\\\V=(0.0625mol)/(0.120M)\\\\V=0.521L`

Thus, the approximate volume is 0.521 L.