Question

A particle moves along a straight line with equation of motion s = t^6-5t^5. Find the value of t (other than 0 ) at which the acceleration is equal to zero.

Answer 1

t = 10/3

Explanation:

`s(t)=t^6-5t^5\\v(t)=6t^5-25t^4\\a(t)=30t^4-100t^3\\\\0=30t^4-100t^3\\0=t^3(30t-100)\\t=0,(10)/(3)`

Therefore, the other value of t is
`t=(10)/(3)`