Question

How many moles of hydrogen are in 3. 06 × 10⁻³ g of glycine , c₂h₅no₂?.

Answer 1

n = 6.06 x
`10^(-4)` mol

Step-by-step explanation:

n =?

m = 3.06 x 10-³ g

M (H5) = 5 x 1.01 (Since we only want hydrogen)

Atomic mass of C = 12.01

Atomic mass of H is 1,01, etc.

Having this data, we can use the Molar mass formula and change it so we can know the quantity of matter (n) in moles, and we just replace it.

M =
`(m)/(n)` ⇔ n =
`(m)/(M)` ⇔ n =
`(3.06 x 10^(-3) )/(5,05)` ⇔ n = 6.06 x
`10^(-4)` mol

Note: The numbers I've used may be different from yours, by a small difference. I don't know if it's the case, but hope it helped.