Answer:
130 coins
Explanation:
We know that:
Shirley and Jim both had 260 coins in total
Shirley had 52 more coins than Jim after Jim gave 1/5 of his coins to her.
Find out: How many coins did Shirley have at first?
Let S be the number of coins Shirley had at first and let J be the number of coins Jim had at first. Jim gave Shirley j/5 coins so now Shirley has s + j/5 and Jim has j - j/5 which is 4j/5 coins.
s + j/5 - 4j/5 = 52 and s + j = 260
s - 3j/5 = 52 and s + j = 260
Subtract the two equations:
8j/5 = 208
Multiply by 5/8
j = 130
s = 260 - 130 = 130
Shirley had 130 coins at first.