Question

What are the coordinates of the vertex of the parabola of y=x^2+8x+16?

Answer 1

(-4,0)

Explanation:

`(-b)/(2a)`

b = 8 and a = 1

`(-8)/(2)` = -4 This is the x term.

To solve for the y term, substitute in -4 for x

`(-4)^(2)` + 8(-4) + 16

16 - 32 + 16

0 This is the y term

(-4,0)

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