Question

This is an 8051 C program to toggle only bit P1.5 continuously every 50 ms. Use Timer 0, mode (16-bit) to create the delay. the crystal frequency is 11.0592MHz.

1. find time delay? (Do the math)
2. find approximate delay? (Do the math)
3. find maximum delay? (Do the math)

Answer 1

1. Time Delay = 50 ms

2. Approximate Delay = 5.0069 ms

3. Maximum Delay = 5.9325 ms

Step-by-step explanation:

To calculate the time delay, approximate delay, and maximum delay for the given program using Timer 0, mode (16-bit), and a crystal frequency of 11.0592MHz, we need to consider the timer calculations and the required time for toggling the bit.

1. Time Delay Calculation:

In 8051 microcontroller, Timer 0 is a 16-bit timer that can count up to 65536. The time delay can be calculated using the following formula:

Time Delay = (65536 - Timer Count) * Machine Cycle Time

The machine cycle time is the time required to execute one machine cycle, and it can be calculated as:

Machine Cycle Time = 1 / Crystal Frequency

For a crystal frequency of 11.0592MHz, the machine cycle time is approximately:

Machine Cycle Time = 1 / 11.0592MHz ≈ 90.52 ns

To toggle the bit every 50 ms, we need to find the Timer Count:

Timer Count = Time Delay / Machine Cycle Time

= 50 ms / 90.52 ns

= 55289

So, the Timer Count is 55289.

2. Approximate Delay Calculation:

The approximate delay can be calculated as follows:

Approximate Delay = Timer Count * Machine Cycle Time

= 55289 * 90.52 ns

= 5.0069 ms

Therefore, the approximate delay is approximately 5.0069 ms.

3. Maximum Delay Calculation:

Since Timer 0 is a 16-bit timer, its maximum count value is 65536. The maximum delay can be calculated as follows:

Maximum Delay = Timer Count * Machine Cycle Time

= 65536 * 90.52 ns

= 5.9325 ms

Therefore, the maximum delay is approximately 5.9325 ms.

To summarize:

1. Time Delay = 50 ms

2. Approximate Delay = 5.0069 ms

3. Maximum Delay = 5.9325 ms