Question

The input of a voltage doubler is 120 Vrms. The dc output is approximately (a) 240 V (b) 60 V (c) 167 V (b) 339 V 32. If the input voltage to a voltage tripler has an rms value of 12 V, the dc output voltage is approximately (a) 36 V (b) 50.9 V (c) 33.9 V (d) 32.4 V

Answer 1

(a) 339 V

(d) 50.9 V

Step-by-step explanation:

(a) The output voltage of a voltage doubler is approximately twice the peak input voltage. The peak voltage of a sinusoidal waveform is Vpeak = sqrt(2) * Vrms. Therefore, for an input voltage of 120 Vrms, the peak voltage is:

peak = sqrt(2) * Vrms = sqrt(2) * 120 V ≈ 169.7 V

The output voltage of the voltage doubler is approximately twice the peak input voltage, which is:

Vout = 2 * Vpeak ≈ 2 * 169.7 V ≈ 339.4 V

Therefore, the dc output voltage of the voltage doubler is approximately 339 V.

(d) The output voltage of a voltage tripler is approximately three times the peak input voltage. Using the same formula as above, the peak voltage of a 12 Vrms input voltage is:

Vpeak = sqrt(2) * Vrms = sqrt(2) * 12 V ≈ 16.97 V

The output voltage of the voltage tripler is approximately three times the peak input voltage, which is:

Vout = 3 * Vpeak ≈ 3 * 16.97 V ≈ 50.9 V

Therefore, the dc output voltage of the voltage tripler is approximately 50.9 V.

So, the answers are:

(a) 339 V

(d) 50.9 V

Answer 2

the answer is C because it is definitely not B and it also can’t be A so it’s C