Answer:
1.207 moles
Step-by-step explanation:
Hi! To solve this problem, we need to use the molar mass of (NH4)2CrO4 and the given mass to find the number of moles of (NH4)2CrO4.
The molar mass of (NH4)2CrO4 can be calculated by adding the atomic masses of all the atoms in the compound.
The atomic masses are:
- N: 14.01 g/mol
- H: 1.01 g/mol
- Cr: 52.00 g/mol
- O: 16.00 g/mol
So, the molar mass of (NH4)2CrO4 is:
(2 x 14.01 g/mol) + (8 x 1.01 g/mol) + 52.00 g/mol + (4 x 16.00 g/mol) = 252.06 g/mol
Now, we can use the given mass and the molar mass to find the number of moles of (NH4)2CrO4:
Number of moles = Mass / Molar mass
Number of moles = 304.2 g / 252.06 g/mol
Number of moles = 1.207 moles
Therefore, there are 1.207 moles of (NH4)2CrO4 in 304.2 g of (NH4)2CrO4.