asked 18.3k views
5 votes
White light containing wavelengths from 410 nm to 750 mm falls on a grating with 7900slits/cm. How wide is the first-order spectrum on a screen 3.70 m away? Express your answer to three significant figures and include the appropriate units.

1 Answer

2 votes

Δy = (3.90 m) * (7.342 x 10^(-3) radians) ≈ 0.0287 m.

To determine the width of the first-order spectrum on a screen 3.90 m away, we need to use the formula for the angular dispersion of a diffraction grating:

Δθ = λ/d,

where Δθ is the angular dispersion, λ is the wavelength, and d is the slit spacing.

First, we need to calculate the average wavelength of the white light by taking the average of the given range:

λ_avg = (410 nm + 750 nm) / 2 = 580 nm.ht

Next, we need to convert the slit spacing from slits/cm to meters:

d = 7900 slits/cm = 7900 slits / (100 cm/m) = 79 slits/m.

Now we can calculate the angular dispersion:

Δθ = λ_avg / d = 580 nm / (79 slits/m) = 7.342 x 10^(-3) radians.

Finally, to find the width of the first-order spectrum on the screen, we can use the relation:

Δy = r * Δθ,

where Δy is the width of the spectrum and r is the distance from the grating to the screen. In this case, r = 3.90 m.

Δy = (3.90 m) * (7.342 x 10^(-3) radians) ≈ 0.0287 m.

Rounded to three significant figures, the width of the first-order spectrum on the screen is approximately 0.0287 m.

answered
User Mr Mo
by
8.5k points