Final answer:
In the titration of NaOH with C4H4O, the molar ratio between NaOH and C4H4O is 3:1. To calculate the moles of NaOH that react with 1 mole of C4H4O, divide the moles of NaOH by the molar ratio. To calculate the volume of a 0.200 M NaOH solution needed to neutralize 345 mL of a 0.0333 M C4H4O solution, use the equation Moles of NaOH = Molarity of NaOH * Volume of NaOH.
Step-by-step explanation:
In the titration of NaOH with C4H4O, the molar ratio between NaOH and C4H4O is 3:1. This means that for every 3 moles of NaOH, 1 mole of C4H4O is neutralized. To calculate the moles of NaOH that react with 1 mole of C4H4O, simply divide the moles of NaOH by the molar ratio. Therefore, 1 mole of C4H4O would react with 3 moles of NaOH.
To calculate the volume of a 0.200 M NaOH solution needed to neutralize 345 mL of a 0.0333 M C4H4O solution, you can use the equation:
Moles of NaOH = Molarity of NaOH * Volume of NaOH
Then, use the moles of NaOH and the molar ratio to calculate the volume:
Volume of NaOH = Moles of NaOH / Molarity of NaOH