Question

I need help with questions 1 &2 !

Answer 1

See below

Explanation:

Question 1

a) The opposite leg of
`\angle A` would be
`\overline{BC}` since it's directly opposite of the angle.

b) The leg adjacent to
`\angle A` is
`\overline{AB}` since it's next/adjacent to the angle

Question 2

5 is the opposite leg of
`\angle M` and 11 is the hypotenuse, so we use the sine function (remember SOHCAHTOA) to solve for the angle:

`\displaystyle \sin M=\frac{\text{Opposite}}{\text{Hypotenuse}}\\\\\sin M=(5)/(11)\\\\M=\sin^(-1)\biggr((5)/(11)\biggr)\\\\M\approx27^\circ`