Question

M = 8 kg

v0 = 6 m/s
F = 8 N
If you wanted the box to reach a distance of x = 10 m in 0.782 seconds, to what value would you change the force (in N)?

Answer 1

Answer: 139 N

Explanation:

`\Delta x=v_0 t+(1)/(2) at^2\\\\10=6(0.782)+(1)/(2)a(0.782)^2\\\\a=(2654000)/(152881) \text{ m/s}^2\\\\ \\ F=ma\\\\F=(8)(2654000/152881)\\\\F=139 \text{ N}`