Question

The equation of line q is y=(1)/(6)x-5. Line r, which is parallel to line q, includes the point (6,2). What is the equation of line r ?

Answer 1

y =
`(1)/(6)`x + 1

Explanation:

y = mx + b

To write the equation we need the slope (m) and the y-intercept (b).

Slope (m):

Parallel lines have the same slope. The slope in the equation is the number before the x. In line q the slope is
`(1)/(6)`, so the slope for line r is also
`(1)/(6)`.

The slope (m) of line r is
`(1)/(6)`.

y-intercept (b):

To find the y-intercept we will use the slope
`(1)/(6)`,the x value of 6 that we get from the point given (6,2) and the y value of 2 also given from the point (6,2)

y = mx + b

2 =
`(1)/(6)`(6) + b Now solve for b

2 = 1 + b Subtract 1 from both sides

1 = b

The y-intercept (b) is 1.

Now that we know the slope (m) of
`(1)/(6)` and the y-intercept (b) of 1, we can write the equation

y = mx + b

y =
`(1)/(6)`x + 1

Helping in the name of Jesus.